Solved Task 2c+d
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@ -15,10 +15,10 @@ Example: A = np.array([[1,2,-1],[4,-2,6],[3,1,0]])
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@author: knaa
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"""
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import numpy as np
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import timeit
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# Aufgabe 2a
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def Serie8_Aufg2(A):
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unknown = 0
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A = np.copy(A) #necessary to prevent changes in the original matrix A_in
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A = A.astype('float64') #change to float
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@ -55,7 +55,7 @@ def Serie8_Aufg2(A):
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if __name__ == '__main__':
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# Beispiel
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# Beispiel aus Skript
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# A = np.array([[1, 2, -1], [4, -2, 6], [3, 1, 0]])
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# b = np.array([
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# [9],
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@ -63,7 +63,7 @@ if __name__ == '__main__':
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# [9]
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# ])
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# Example from Task 1
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# Beispiel aus Aufgabe 1
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A = np.array([
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[1, -2, 3],
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[-5, 4, 1],
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@ -77,6 +77,7 @@ if __name__ == '__main__':
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[Q,R]=Serie8_Aufg2(A)
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# Aufgabe 2b
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n = len(b) - 1
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QTb = Q.T @ b
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result = [0 for i in range(n+1)]
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@ -94,3 +95,26 @@ if __name__ == '__main__':
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print("\nQ:\n", Q)
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print("\nR:\n", R)
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print("\Result:\n", result)
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# Aufgabe 2c
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t1 = timeit.repeat("Serie8_Aufg2(A)", "from __main__ import Serie8_Aufg2, A", number=100)
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t2 = timeit.repeat("np.linalg.qr(A)", "from __main__ import np, A", number=100)
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avg_t1 = np.average(t1) / 100
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avg_t2 = np.average(t2) / 100
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print("Geschwindigkeit mit 3x3 Matrix:")
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print("Benötigte Zeit mit eigener Funktion:", avg_t1)
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print("Benötigte Zeit mit Numpy:", avg_t2)
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# Aufgabe 2d
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Test = np.random.rand(100,100)
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t1 = timeit.repeat("Serie8_Aufg2(Test)", "from __main__ import Serie8_Aufg2, Test", number=100)
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t2 = timeit.repeat("np.linalg.qr(Test)", "from __main__ import np, Test", number=100)
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avg_t1 = np.average(t1) / 100
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avg_t2 = np.average(t2) / 100
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print("Geschwindigkeit mit 100x100 Matrix:")
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print("Benötigte Zeit mit eigener Funktion:", avg_t1)
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print("Benötigte Zeit mit Numpy:", avg_t2)
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# Die von Numpy zur Verfügung gestellt Funktion ist wesentlich effizienter.
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